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Popular >

y-y^'+y=0

Solution

y - y^{^{'}} + y = 0

Solution

y = e^{2 t + c_{1}}

Solution steps

y - y^{'} (t) + y = 0

Solve separable ODE:

y = e^{2 t + c_{1}}

y = e^{2 t + c_{1}}

Popular Examples

2sin(y^2)+tycos(y^2)y^'=0

2 sin (y^{2}) + t y cos (y^{2}) y^{^{'}} = 0

x^2sin(3y)+cos(3y)(dy)/(dx)=4x^2

x^{2} sin (3 y) + cos (3 y) \frac{d y}{d x} = 4 x^{2}

(dy)/(dx)-5(dy)/(dx)+6y=0

\frac{d y}{d x} - 5 \frac{d y}{d x} + 6 y = 0

(dy)/(dt)=yt^2-y

\frac{d y}{d t} = y t^{2} - y

xy-x(dy)/(dx)=2x,y(-1)=3

x y - x \frac{d y}{d x} = 2 x, y (- 1) = 3

Frequently Asked Questions (FAQ)

What is the solution for y-y^'+y=0 ?
The solution for y-y^'+y=0 is y=e^{2t+c_{1}}