What is the sum from n=1 to infinity of (n^3)/(5^n) ?

The sum from n=1 to infinity of (n^3)/(5^n) is converges

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sum from n=1 to infinity of (n^3)/(5^n)

n = 1 \sum \infty \frac{n ^{3}}{5 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{n ^{3}}{5 ^{n}}

Apply Series Ratio Test:

converges

= converges

\int \frac{7 t - 4}{t + 1} d t

\frac{d y}{d x} = 9 y \cdot e^{x + 9}

n = 1 \sum \infty \frac{n}{n ^{3} + n ^{2}}

y^{^{''}} + 2 y^{^{'}} = x^{2} + e^{- 2 x}

f (x) = x, at x = 64.2

What is the sum from n=1 to infinity of (n^3)/(5^n) ?
The sum from n=1 to infinity of (n^3)/(5^n) is converges