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Popular >

y^'=x-4xy

Solution

y^{^{'}} = x - 4 x y

Solution

y = \frac{e ^{- 2 x^{2} + c_{1}}}{4} + \frac{1}{4}

Solution steps

y^{'} (x) = x - 4 x y

Solve separable ODE:

y = \frac{e ^{- 2 x^{2} + c_{1}}}{4} + \frac{1}{4}

y = \frac{e ^{- 2 x^{2} + c_{1}}}{4} + \frac{1}{4}

Popular Examples

(dy)/(dx)y=arccos(5x^5)

\frac{d y}{d x} y = arccos (5 x^{5})

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\frac{d x}{d t} = \frac{3}{x e ^{t + 7 x}}

y^'sin(y)=cos(x),y(0)=0

y^{^{'}} sin (y) = cos (x), y (0) = 0

\frac{d x}{d t} + 1 = x

e^y(1+x^2)(dy)/(dx)-2(1+e^y)=0

e^{y} (1 + x^{2}) \frac{d y}{d x} - 2 (1 + e^{y}) = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'=x-4xy ?
The solution for y^'=x-4xy is y=(e^{-2x^2+c_{1}})/4+1/4