What is the solution for (dy)/(dx)=-2/4 x^3y^8 ?

The solution for (dy)/(dx)=-2/4 x^3y^8 is y=-\sqrt[7]{8/(7(-x^4+c_{1))}}

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(dy)/(dx)=-2/4 x^3y^8

\frac{d y}{d x} = - \frac{2}{4} x^{3} y^{8}

Solution steps

\frac{d y}{d x} = - \frac{2}{4} x^{3} y^{8}

Solve separable ODE:

\frac{d y}{d t} = \frac{0.002 \cdot ( - 4.43 y )}{10}

x^{3} \frac{d y}{d x} + 4 y^{2} = 0, y (1) = 1

2 x y^{^{'}} ln (x) = - 2 y

y^{^{'}} sec (t) = \frac{- y ^{23}}{22}

\frac{d y}{d x} 6 cos (4 x) sin (2 y) = 1

What is the solution for (dy)/(dx)=-2/4 x^3y^8 ?
The solution for (dy)/(dx)=-2/4 x^3y^8 is y=-\sqrt[7]{8/(7(-x^4+c_{1))}}