What is the solution for xdy=(y^{-3}-y)dx ?

The solution for xdy=(y^{-3}-y)dx is y=(\sqrt[4]{-c_{1}+x^4})/x ,y=-(\sqrt[4]{-c_{1}+x^4})/x

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xdy=(y^{-3}-y)dx

x d y = (y^{- 3} - y) d x

Solution steps

x d y = (y^{- 3} - y) d x

Solve separable ODE:

y^{^{'}} = - 2 t \frac{( 1 + y ^{2} )}{y}

\frac{d y}{d t} = 2 t y

x \frac{d y}{d x} + 6 y = 3 x y

y^{^{'}} = - 0.2 y, y (0) = c e^{0.2 t}

\frac{d y}{d x} + 12 x^{2} y = 7 x^{2}, y (0) = 2

What is the solution for xdy=(y^{-3}-y)dx ?
The solution for xdy=(y^{-3}-y)dx is y=(\sqrt[4]{-c_{1}+x^4})/x ,y=-(\sqrt[4]{-c_{1}+x^4})/x