What is the solution for (xy+3x-y-3)/(xy-2x+4y-8)=(dy)/(dx) ?

The solution for (xy+3x-y-3)/(xy-2x+4y-8)=(dy)/(dx) is y=-5\W(-(x+4}{5e^{\frac{x+c_{1}+3)/5}})-3

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(xy+3x-y-3)/(xy-2x+4y-8)=(dy)/(dx)

\frac{x y + 3 x - y - 3}{x y - 2 x + 4 y - 8} = \frac{d y}{d x}

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

Solution steps

\frac{x y + 3 x - y - 3}{x y - 2 x + 4 y - 8} = \frac{d y}{d x}

Solve separable ODE:

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

y = - 5 W (- \frac{x + 4}{5 e ^{\frac{x + c _{1} + 3}{5}}}) - 3

(t^{2} - 14 t + 45) \frac{d y}{d t} = y

\frac{d y}{d x} = y^{2} (7 - e^{x})

y^{^{'}} = 3 y - 7

y^{^{'}} = 3 y - 6

y^{^{'}} = 3 y - 2

What is the solution for (xy+3x-y-3)/(xy-2x+4y-8)=(dy)/(dx) ?
The solution for (xy+3x-y-3)/(xy-2x+4y-8)=(dy)/(dx) is y=-5\W(-(x+4}{5e^{\frac{x+c_{1}+3)/5}})-3