What is the solution for (x^2+3)(dy)/(dx)=xe^y ?

The solution for (x^2+3)(dy)/(dx)=xe^y is y=-ln(-1/2 ln(x^2+3)-c_{1})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2+3)(dy)/(dx)=xe^y

(x^{2} + 3) \frac{d y}{d x} = x e^{y}

y = - ln (- \frac{1}{2} ln (x^{2} + 3) - c_{1})

Solution steps

(x^{2} + 3) \frac{d y}{d x} = x e^{y}

Solve separable ODE:

y = - ln (- \frac{1}{2} ln (x^{2} + 3) - c_{1})

y = - ln (- \frac{1}{2} ln (x^{2} + 3) - c_{1})

\frac{d y}{d x} = 2 x y + 5 y, y (0) = 3

x ln (x) d y - y d x = 0

\frac{d y}{d x} = e^{x - y}, y (0) = ln (4)

\frac{d y}{d x} = \frac{tan ( y )}{x}

5 x^{2} d y = \frac{x ^{4} \cdot e ^{3 x}}{y ^{2}} d x

What is the solution for (x^2+3)(dy)/(dx)=xe^y ?
The solution for (x^2+3)(dy)/(dx)=xe^y is y=-ln(-1/2 ln(x^2+3)-c_{1})