What is the solution for y^'+sin^2(x)y=cos^2(x)y ?

The solution for y^'+sin^2(x)y=cos^2(x)y is y=e^{1/2 sin(2x)+c_{1}}

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y^'+sin^2(x)y=cos^2(x)y

y^{^{'}} + sin^{2} (x) y = cos^{2} (x) y

y = e^{\frac{1}{2} s i n (2 x) + c_{1}}

Solution steps

y^{'} (x) + sin^{2} (x) y = cos^{2} (x) y

Solve separable ODE:

y = e^{\frac{1}{2} s i n (2 x) + c_{1}}

y = e^{\frac{1}{2} s i n (2 x) + c_{1}}

\frac{d y}{d x} = 2 y, y (3) = 2 e^{- 2}

y^{^{'}} + \frac{33 y}{3090} - \frac{17}{2} = 0

\frac{d}{d x} (x^{2} + y^{2}) = 2 x y

\frac{d y}{d x} y = x + 5

(\frac{( 5 y )}{( x ) - 24 x ^{(2)}}) d x + 5 d y = 0

What is the solution for y^'+sin^2(x)y=cos^2(x)y ?
The solution for y^'+sin^2(x)y=cos^2(x)y is y=e^{1/2 sin(2x)+c_{1}}