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Popular >

y^'-x^2y^2=x^2

Solution

y^{^{'}} - x^{2} y^{2} = x^{2}

Solution

y = tan (\frac{x ^{3}}{3} + c_{1})

Solution steps

y^{'} (x) - x^{2} y^{2} = x^{2}

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + c_{1})

y = tan (\frac{x ^{3}}{3} + c_{1})

Popular Examples

(dy)/(dx)-3xy=0

\frac{d y}{d x} - 3 x y = 0

y^'+2xy=6xy^{-2}

y^{^{'}} + 2 x y = 6 x y^{- 2}

(dy)/(dx)=3x^2y^2,y\ne 0

\frac{d y}{d x} = 3 x^{2} y^{2}, y \neq = 0

y^'+12xcos(x)e^y=0

y^{^{'}} + 12 x cos (x) e^{y} = 0

(dy)/(dx)y=(x^3-2x^2+7)^{5/2}

\frac{d y}{d x} y = (x^{3} - 2 x^{2} + 7)^{\frac{5}{2}}

Frequently Asked Questions (FAQ)

What is the solution for y^'-x^2y^2=x^2 ?
The solution for y^'-x^2y^2=x^2 is y=tan((x^3)/3+c_{1})