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Popular >

y^'-y/((ln(y))^2)=0

Solution

y^{^{'}} - \frac{y}{( ln ( y ) ) ^{2}} = 0

Solution

Solution steps

y^{'} (t) - \frac{y}{( ln ( y ) ) ^{2}} = 0

Solve separable ODE:

Popular Examples

(3x^2+2)^3(dy)/(dx)-xy^2=0,y(0)=2

(3 x^{2} + 2)^{3} \frac{d y}{d x} - x y^{2} = 0, y (0) = 2

(dy)/(dt)=4(1-y)^2

\frac{d y}{d t} = 4 (1 - y)^{2}

y + x y^{^{'}} = 9

(1+e^x)y^'=y-ye^x

(1 + e^{x}) y^{^{'}} = y - y e^{x}

(dy)/(dx)= x/(y^2),y(0)=2

\frac{d y}{d x} = \frac{x}{y ^{2}}, y (0) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'-y/((ln(y))^2)=0 ?
The solution for y^'-y/((ln(y))^2)=0 is y=e^{\sqrt[3]{3t+c_{1}}}