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Popular >

y^'= x/(y+1),y(2)=-2

Solution

y^{^{'}} = \frac{x}{y + 1}, y (2) = - 2

Solution

y = - x^{2} - 3 - 1

Solution steps

y^{'} (x) = \frac{x}{y + 1}

Solve separable ODE:

y = - x^{2} - 3 - 1

y = - x^{2} - 3 - 1

Popular Examples

(dy)/(dt)= t/(t^2y+y),y(0)=8

\frac{d y}{d t} = \frac{t}{t ^{2} y + y}, y (0) = 8

4 y^{^{'}} + 16 y = 8

3 y^{^{'}} + 2 y = 1 2^{2}

y - 14 y^{^{'}} + 50 y = 0

(dy)/(dx)y=ln^8(sqrt((4+x^2)/(4-x^2)))

\frac{d y}{d x} y = ln^{8} (\frac{4 + x ^{2}}{4 - x ^{2}})

Frequently Asked Questions (FAQ)

What is the solution for y^'= x/(y+1),y(2)=-2 ?
The solution for y^'= x/(y+1),y(2)=-2 is y=-sqrt(x^2-3)-1