What is the tangent of y=4e^xcos(x),4,\at x=0 ?

The tangent of y=4e^xcos(x),4,\at x=0 is y=4x+4

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tangent of y=4e^xcos(x),4,\at x=0

tangent of

y = 4 e^{x} cos (x), 4, at x = 0

y = 4 x + 4

Solution steps

Find the tangent point:

(0, 4)

Find the slope of

y = 4 e^{x} cos (x) : \frac{d y}{d x} = 4 (e^{x} cos (x) - e^{x} sin (x))

Compute the slope of

y = 4 e^{x} cos (x)

x = 0 : m = 4

Find the line with slope m=

4

and passing through

(0, 4) : y = 4 x + 4

y = 4 x + 4

\frac{d y}{d x} y = 4 x^{2} + 2

\frac{5}{s}

\int_{1}^{6} \frac{x}{2} + \frac{1}{2 x} d x

\int e^{- \frac{1}{2 x}} d x

m (x) = x^{3} - x^{2} + 1

What is the tangent of y=4e^xcos(x),4,\at x=0 ?
The tangent of y=4e^xcos(x),4,\at x=0 is y=4x+4