What is the solution for (dy)/(dx)=-3/4 x^4y^3 ?

The solution for (dy)/(dx)=-3/4 x^4y^3 is y=sqrt(-(10)/(-3x^5+c_{1))},y=-sqrt(-(10)/(-3x^5+c_{1))}

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(dy)/(dx)=-3/4 x^4y^3

\frac{d y}{d x} = - \frac{3}{4} x^{4} y^{3}

y = - \frac{10}{- 3 x ^{5} + c _{1}}, y = - - \frac{10}{- 3 x ^{5} + c _{1}}

Solution steps

\frac{d y}{d x} = - \frac{3}{4} x^{4} y^{3}

Solve separable ODE:

y = - \frac{10}{- 3 x ^{5} + c _{1}}, y = - - \frac{10}{- 3 x ^{5} + c _{1}}

y = - \frac{10}{- 3 x ^{5} + c _{1}}, y = - - \frac{10}{- 3 x ^{5} + c _{1}}

y^{2} (3 v + 1) d v + y^{2} (- v^{2}) d y = 0

y^{^{'}} = \frac{x ( x + 1 )}{4 y ^{3}}

5 y y^{^{'}} = x, y (5) = 2

y^{^{'}} = - y \cdot 0.04 + 3.5 \cdot 0.5

5 x^{^{'}} + 7 x = 15

What is the solution for (dy)/(dx)=-3/4 x^4y^3 ?
The solution for (dy)/(dx)=-3/4 x^4y^3 is y=sqrt(-(10)/(-3x^5+c_{1))},y=-sqrt(-(10)/(-3x^5+c_{1))}