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Popular >

y^'+2y=-4

Solution

y^{^{'}} + 2 y = - 4

Solution

y = e^{- 2 t + c_{1}} - 2

Solution steps

y^{'} (t) + 2 y = - 4

Solve separable ODE:

y = e^{- 2 t + c_{1}} - 2

y = e^{- 2 t + c_{1}} - 2

Popular Examples

y^'=-(5x^4-5)/(4y)

y^{^{'}} = - \frac{5 x ^{4} - 5}{4 y}

(e^4-y)cos(x)(dy)/(dx)=e^4sin(x)

(e^{4} - y) cos (x) \frac{d y}{d x} = e^{4} sin (x)

y^'=y-2y^2,y(0)=t(t)

y^{^{'}} = y - 2 y^{2}, y (0) = t (t)

(dy)/(dx)=-4/9 x^6y^4

\frac{d y}{d x} = - \frac{4}{9} x^{6} y^{4}

y^'=(cos(x))y^2

y^{^{'}} = (cos (x)) y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=-4 ?
The solution for y^'+2y=-4 is y=e^{-2t+c_{1}}-2