en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'e^{-x}=y^2

Solution

y^{^{'}} e^{- x} = y^{2}

Solution

y = - \frac{1}{e ^{x} + c _{1}}

Solution steps

y^{'} (x) e^{- x} = y^{2}

Solve separable ODE:

y = - \frac{1}{e ^{x} + c _{1}}

y = - \frac{1}{e ^{x} + c _{1}}

Popular Examples

y^{2} d y = x^{2} d x

y^'+((2x)/(x^2-1))y= x/(x^2-1)

y^{^{'}} + (\frac{2 x}{x ^{2} - 1}) y = \frac{x}{x ^{2} - 1}

sin(x)(dy)/(dx)+ycos(x)=0,y(pi/2)=1

sin (x) \frac{d y}{d x} + y cos (x) = 0, y (\frac{π}{2}) = 1

(dy)/(dx)=x^3sqrt(6y)

\frac{d y}{d x} = x^{3} 6 y

(dS)/(dt)=0.05-S/((945/2))

\frac{d S}{d t} = 0.05 - \frac{S}{( \frac{945}{2} )}

Frequently Asked Questions (FAQ)

What is the solution for y^'e^{-x}=y^2 ?
The solution for y^'e^{-x}=y^2 is y=-1/(e^x+c_{1)}