en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=-y*cos(x)

Solution

y^{^{'}} = - y \cdot cos (x)

Solution

y = e^{- s i n (x) + c_{1}}

Solution steps

y^{'} (x) = - y \cdot cos (x)

Solve separable ODE:

y = e^{- s i n (x) + c_{1}}

y = e^{- s i n (x) + c_{1}}

Popular Examples

y^2sec(5x)(dy)/(dx)=1,y(0)=0

y^{2} sec (5 x) \frac{d y}{d x} = 1, y (0) = 0

\frac{d y}{d t} = 8 - y

(dy)/(dx)=(-e^x(y-1))/(2(e^x+4))

\frac{d y}{d x} = \frac{- e ^{x} ( y - 1 )}{2 ( e ^{x} + 4 )}

y^'cos(y)+2xsin(y)=-2x

y^{^{'}} cos (y) + 2 x sin (y) = - 2 x

y^{^{'}} = y^{2} + y - 30

Frequently Asked Questions (FAQ)

What is the solution for y^'=-y*cos(x) ?
The solution for y^'=-y*cos(x) is y=e^{-sin(x)+c_{1}}