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Popular >

y^'=-xy+4x

Solution

y^{^{'}} = - x y + 4 x

Solution

y = e^{- \frac{x ^{2}}{2} + c_{1}} + 4

Solution steps

y^{'} (x) = - x y + 4 x

Solve separable ODE:

y = e^{- \frac{x ^{2}}{2} + c_{1}} + 4

y = e^{- \frac{x ^{2}}{2} + c_{1}} + 4

Popular Examples

derivative of tan(y)=x

\frac{d}{d x} (tan (y)) = x

(xy^2+3y^2)dy-9ydx=0

(x y^{2} + 3 y^{2}) d y - 9 y d x = 0

(dy}{dx}=\frac{2x)/y ,y(1)=1

\frac{d y}{d x} = \frac{2 x}{y}, y (1) = 1

xdy=(1/(y^2)-y)dx

x d y = (\frac{1}{y ^{2}} - y) d x

(dy)/(dx)=(3x^2-e^x)/(2y-5),y(0)=1

\frac{d y}{d x} = \frac{3 x ^{2} - e ^{x}}{2 y - 5}, y (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=-xy+4x ?
The solution for y^'=-xy+4x is y=e^{-(x^2)/2+c_{1}}+4