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Popular >

y^'=y^2*x

Solution

y^{^{'}} = y^{2} \cdot x

Solution

y = - \frac{2}{x ^{2} + c _{1}}

Solution steps

y^{'} (x) = y^{2} \cdot x

Solve separable ODE:

y = - \frac{2}{x ^{2} + c _{1}}

y = - \frac{2}{x ^{2} + c _{1}}

Popular Examples

xy^2+yy^'=x^2yy^'

x y^{2} + y y^{^{'}} = x^{2} y y^{^{'}}

(x^2}{y^2-1}(dy)/(dx)=\frac{3x^3)/y

\frac{x ^{2}}{y ^{2} - 1} \frac{d y}{d x} = \frac{3 x ^{3}}{y}

(dQ)/(dt)+0.05Q=0

\frac{d Q}{d t} + 0.05 Q = 0

y^'=(2+3x)sqrt(y),y(0)=3

y^{^{'}} = (2 + 3 x) y, y (0) = 3

y^'(s)=((1-2s)/(s^2))y(s)

y^{^{'}} (s) = (\frac{1 - 2 s}{s ^{2}}) y (s)

Frequently Asked Questions (FAQ)

What is the solution for y^'=y^2*x ?
The solution for y^'=y^2*x is y=-2/(x^2+c_{1)}