What is the solution for (dy)/(dx)=(xy-x^3y)/(1-y) ?

The solution for (dy)/(dx)=(xy-x^3y)/(1-y) is y=-\W(-1/(e^{(x^4-2x^2-c_{1))/4}})

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(dy)/(dx)=(xy-x^3y)/(1-y)

\frac{d y}{d x} = \frac{x y - x ^{3} y}{1 - y}

y = - W (- \frac{1}{e ^{\frac{x ^{4} - 2 x ^{2} - c _{1}}{4}}})

Solution steps

\frac{d y}{d x} = \frac{x y - x ^{3} y}{1 - y}

Solve separable ODE:

y = - W (- \frac{1}{e ^{\frac{x ^{4} - 2 x ^{2} - c _{1}}{4}}})

y = - W (- \frac{1}{e ^{\frac{x ^{4} - 2 x ^{2} - c _{1}}{4}}})

x d y - y d x = 0, y (1) = 2

\frac{d y}{d x} = \frac{y}{x}, y (5) = 20

\frac{d y}{d x} = - \frac{3}{7} x^{6} y^{5}

y^{^{'}} = (sin^{5} (x) cos^{2} (x)) (y^{2} + 1), y (0) = 0

3 e^{x} \cdot tan (y) d x + (2 - e^{x}) sec^{2} (y) d y = 0

What is the solution for (dy)/(dx)=(xy-x^3y)/(1-y) ?
The solution for (dy)/(dx)=(xy-x^3y)/(1-y) is y=-\W(-1/(e^{(x^4-2x^2-c_{1))/4}})