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Popular >

y^'-4y=6,y(0)=0

Solution

y^{^{'}} - 4 y = 6, y (0) = 0

Solution

y = \frac{3 e ^{4 t}}{2} - \frac{3}{2}

Solution steps

y^{'} (t) - 4 y = 6

Solve separable ODE:

y = \frac{3 e ^{4 t}}{2} - \frac{3}{2}

y = \frac{3 e ^{4 t}}{2} - \frac{3}{2}

Popular Examples

(dy)/(dx)+5y=-4

\frac{d y}{d x} + 5 y = - 4

y^'=(-(3y^2+1)x)/(x^2+1)

y^{^{'}} = \frac{- ( 3 y ^{2} + 1 ) x}{x ^{2} + 1}

derivative of 7x^2+8ln(xy)=14

\frac{d}{d x} (7 x^{2} + 8 ln (x y)) = 14

y^'=(4x)/(1+2y),y(2)=0

y^{^{'}} = \frac{4 x}{1 + 2 y}, y (2) = 0

y^'=-9/4 x^6y^4

y^{^{'}} = - \frac{9}{4} x^{6} y^{4}

Frequently Asked Questions (FAQ)

What is the solution for y^'-4y=6,y(0)=0 ?
The solution for y^'-4y=6,y(0)=0 is y=(3e^{4t})/2-3/2