What is the solution for dy=(y+1)/(x+4)dx ?

The solution for dy=(y+1)/(x+4)dx is y=e^{c_{1}}x+4e^{c_{1}}-1

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dy=(y+1)/(x+4)dx

d y = \frac{y + 1}{x + 4} d x

y = e^{c_{1}} x + 4 e^{c_{1}} - 1

Solution steps

d y = \frac{y + 1}{x + 4} d x

Solve separable ODE:

y = e^{c_{1}} x + 4 e^{c_{1}} - 1

y = e^{c_{1}} x + 4 e^{c_{1}} - 1

y^{^{'}} = (15 x^{2} + 4) (6 y + 5)

x tan (y) + (1 + x^{2}) \frac{d y}{d x} = 0

\frac{d P}{d t} = a P (t) - b P (t)^{2}

y - 2 y^{^{'}} + 10 y = 0

\frac{d v}{d t} = 10 - \frac{1}{100} v, v = 0, t = 0

What is the solution for dy=(y+1)/(x+4)dx ?
The solution for dy=(y+1)/(x+4)dx is y=e^{c_{1}}x+4e^{c_{1}}-1