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Popular >

y^'=-ky^2

Solution

y^{^{'}} = - k y^{2}

Solution

y = - \frac{1}{- k t + c _{1}}

Solution steps

y^{'} (t) = - k y (t)^{2}

Solve separable ODE:

y = - \frac{1}{- k t + c _{1}}

y = - \frac{1}{- k t + c _{1}}

Popular Examples

y^'=3(y-1)^{2/3},y(0)=1

y^{^{'}} = 3 (y - 1)^{\frac{2}{3}}, y (0) = 1

2sqrt(x)y^'=cos^2(y),y(0)=2

2 x y^{^{'}} = cos^{2} (y), y (0) = 2

(dy)/(dx)=(2x)/(-8y-6)

\frac{d y}{d x} = \frac{2 x}{- 8 y - 6}

(dy)/(dx)=(y^2x)

\frac{d y}{d x} = (y^{2} x)

2yy^'=1,y(0)=sqrt(x-1)

2 y y^{^{'}} = 1, y (0) = x - 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=-ky^2 ?
The solution for y^'=-ky^2 is y=-1/(-kt+c_{1)}