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Popular >

(6x-1)y^'+6y=0

Solution

(6 x - 1) y^{^{'}} + 6 y = 0

Solution

y = \frac{c _{1}}{6 x - 1}

Solution steps

(6 x - 1) y^{'} (x) + 6 y = 0

Solve separable ODE:

y = \frac{c _{1}}{6 x - 1}

y = \frac{c _{1}}{6 x - 1}

Graph

Popular Examples

(dy)/(dx)=-y/(4320/7)

\frac{d y}{d x} = - \frac{y}{\frac{4320}{7}}

(1-x^2)ydy-xe^{-y}dx=0,y(0)=0

(1 - x^{2}) y d y - x e^{- y} d x = 0, y (0) = 0

(e^xy)y^'=e^{-y}+e^{-2x-y}

(e^{x} y) y^{^{'}} = e^{- y} + e^{- 2 x - y}

(1+cos(x))y^'=(1+e^{-y})sin(x),y(0)=0

(1 + cos (x)) y^{^{'}} = (1 + e^{- y}) sin (x), y (0) = 0

(dy)/(dx)=-(0.6)/(cos(y))

\frac{d y}{d x} = - \frac{0.6}{cos ( y )}

Frequently Asked Questions (FAQ)

What is the solution for (6x-1)y^'+6y=0 ?
The solution for (6x-1)y^'+6y=0 is y=(c_{1})/(6x-1)