What is the solution for (dy)/(dx)= x/y ,y(0)=-1 ?

The solution for (dy)/(dx)= x/y ,y(0)=-1 is y=-sqrt(x^2+1)

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(dy)/(dx)= x/y ,y(0)=-1

\frac{d y}{d x} = \frac{x}{y}, y (0) = - 1

y = - x^{2} + 1

Solution steps

\frac{d y}{d x} = \frac{x}{y}

Solve separable ODE:

y = - x^{2} + 1

y = - x^{2} + 1

\frac{d P}{d t} = 8 Pt, P (1) = 6

y^{^{'}} = cos (t) \cdot y

y^{2} sec (2 x) \frac{d y}{d x} = 1, y (0) = 0

x y^{3} d x + e^{x^{3}} d y = 0

\frac{d y}{d x} = \frac{y sin ( x )}{y + 1}

What is the solution for (dy)/(dx)= x/y ,y(0)=-1 ?
The solution for (dy)/(dx)= x/y ,y(0)=-1 is y=-sqrt(x^2+1)