What is the tangent of f(x)=12(x-(1/x))^4,\at x=2 ?

The tangent of f(x)=12(x-(1/x))^4,\at x=2 is y= 405/2 x-1377/4

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tangent of f(x)=12(x-(1/x))^4,\at x=2

tangent of

f (x) = 12 (x - (\frac{1}{x}))^{4}, at x = 2

y = \frac{405}{2} x - \frac{1377}{4}

Solution steps

Find the tangent point:

(2, \frac{243}{4})

Find the slope of

f (x) = 12 (x - \frac{1}{x})^{4} : \frac{df ( x )}{d x} = 48 (x - \frac{1}{x})^{3} (1 + \frac{1}{x ^{2}})

Compute the slope of

f (x) = 12 (x - \frac{1}{x})^{4}

x = 2 : m = \frac{405}{2}

Find the line with slope m=

\frac{405}{2}

and passing through

(2, \frac{243}{4}) : y = \frac{405}{2} x - \frac{1377}{4}

y = \frac{405}{2} x - \frac{1377}{4}

\frac{d r}{d s} = 0.05 r

x \to 0 lim (sin (\frac{1}{x}) \cdot x)

\int (cot (b) θ + tan (b) θ)^{2} d θ

n = 0 \sum \infty \frac{9 n !}{n ^{n}}

What is the tangent of f(x)=12(x-(1/x))^4,\at x=2 ?
The tangent of f(x)=12(x-(1/x))^4,\at x=2 is y= 405/2 x-1377/4