What is the solution for (dy}{dx}+\frac{3y)/x = 3/x ?

The solution for (dy}{dx}+\frac{3y)/x = 3/x is y=(c_{1})/(x^3)+1

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(dy}{dx}+\frac{3y)/x = 3/x

\frac{d y}{d x} + \frac{3 y}{x} = \frac{3}{x}

y = \frac{c _{1}}{x ^{3}} + 1

Solution steps

\frac{d y}{d x} + \frac{3 y}{x} = \frac{3}{x}

Solve separable ODE:

y = \frac{c _{1}}{x ^{3}} + 1

y = \frac{c _{1}}{x ^{3}} + 1

\frac{d y}{y} = 3 x^{2} d x

x sin (x) y^{^{'}} - (sin (x) + x cos (x)) y = 0

(1 + y) - (1 - x) y^{^{'}} = 0

\frac{d y}{d x} = \frac{x}{y} - \frac{x}{1 + y}, y (0) = 1

(1 + x^{2}) d y + y d x = 0

What is the solution for (dy}{dx}+\frac{3y)/x = 3/x ?
The solution for (dy}{dx}+\frac{3y)/x = 3/x is y=(c_{1})/(x^3)+1