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Popular >

y^'=-2y-4

Solution

y^{^{'}} = - 2 y - 4

Solution

y = e^{- 2 t + c_{1}} - 2

Solution steps

y^{'} (t) = - 2 y - 4

Solve separable ODE:

y = e^{- 2 t + c_{1}} - 2

y = e^{- 2 t + c_{1}} - 2

Popular Examples

y^{^{'}} = - 2 y - 6

(dy)/(dx)+9x^2y=2x^2,y(0)=1

\frac{d y}{d x} + 9 x^{2} y = 2 x^{2}, y (0) = 1

y^'=8x^3e^{-2y},y(1)=0

y^{^{'}} = 8 x^{3} e^{- 2 y}, y (1) = 0

(dy)/(dx)=e^{-y},y(0)=0

\frac{d y}{d x} = e^{- y}, y (0) = 0

y(dy)/(dx)=3x(y^2+6)^8

y \frac{d y}{d x} = 3 x (y^{2} + 6)^{8}

Frequently Asked Questions (FAQ)

What is the solution for y^'=-2y-4 ?
The solution for y^'=-2y-4 is y=e^{-2t+c_{1}}-2