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Popular >

y^'=-0.3y

Solution

y^{^{'}} = - 0.3 y

Solution

y = e^{- 0.3 t + c_{1}}

Solution steps

y^{'} (t) = - 0.3 y

Solve separable ODE:

y = e^{- 0.3 t + c_{1}}

y = e^{- 0.3 t + c_{1}}

Popular Examples

(dy)/(dx)=x^4y^{-7},y(0)=3

\frac{d y}{d x} = x^{4} y^{- 7}, y (0) = 3

(dy)/(dx)=((1+y)/(2+x))

\frac{d y}{d x} = (\frac{1 + y}{2 + x})

y^'=((3x^2-e^x))/(2y-5),y(0)=1

y^{^{'}} = \frac{( 3 x ^{2} - e ^{x} )}{2 y - 5}, y (0) = 1

y^'=(y-a)/(b-x)

y^{^{'}} = \frac{y - a}{b - x}

(dy)/(dx)=x-xy-y+1

\frac{d y}{d x} = x - x y - y + 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=-0.3y ?
The solution for y^'=-0.3y is y=e^{-0.3t+c_{1}}