What is the solution for (x^2+4)(dy)/(dx)+xy=2x,y(0)=3 ?

The solution for (x^2+4)(dy)/(dx)+xy=2x,y(0)=3 is y= 2/(sqrt(x^2+4))+2

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(x^2+4)(dy)/(dx)+xy=2x,y(0)=3

(x^{2} + 4) \frac{d y}{d x} + x y = 2 x, y (0) = 3

y = \frac{2}{x ^{2} + 4} + 2

Solution steps

(x^{2} + 4) \frac{d y}{d x} + x y = 2 x

Solve separable ODE:

y = \frac{2}{x ^{2} + 4} + 2

y = \frac{2}{x ^{2} + 4} + 2

\frac{d x}{d t} = x sin (t), x (0) = 3

x y^{^{'}} = \frac{3 y ^{3} + 12 y x ^{2}}{2 y ^{2} + 8 x ^{2}}

\frac{d y}{d x} = x y + 6 x + 3 y + 18

y^{^{'}} - 4 y^{2} e^{- 4 x} = 0, y (0) = 4

d x + y d y = x^{2} y d y

What is the solution for (x^2+4)(dy)/(dx)+xy=2x,y(0)=3 ?
The solution for (x^2+4)(dy)/(dx)+xy=2x,y(0)=3 is y= 2/(sqrt(x^2+4))+2