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Popular >

y^'=(-2y+xy)/(x^2)

Solution

y^{^{'}} = \frac{- 2 y + x y}{x ^{2}}

Solution

y = e^{\frac{2}{x} + c_{1}} x

Solution steps

y^{'} (x) = \frac{- 2 y + x y}{x ^{2}}

Solve separable ODE:

y = e^{\frac{2}{x} + c_{1}} x

y = e^{\frac{2}{x} + c_{1}} x

Graph

Popular Examples

(dy)/(dx)=((y+3)(x-1))/((y-2)(x+4))

\frac{d y}{d x} = \frac{( y + 3 ) ( x - 1 )}{( y - 2 ) ( x + 4 )}

(dy)/(dx)y= 5/(cos(x))+1/(tan(x))

\frac{d y}{d x} y = \frac{5}{cos ( x )} + \frac{1}{tan ( x )}

1/2 (dy)/(dt)+10y=12,y(0)=0

\frac{1}{2} \frac{d y}{d t} + 10 y = 12, y (0) = 0

y^'=(6xy^3)/(e^{3x)}

y^{^{'}} = \frac{6 x y ^{3}}{e ^{3 x}}

y^{^{'}} = 3 y (1 - \frac{y}{4})

Frequently Asked Questions (FAQ)

What is the solution for y^'=(-2y+xy)/(x^2) ?
The solution for y^'=(-2y+xy)/(x^2) is y=e^{2/x+c_{1}}x