What is the solution for (dy}{dx}=\frac{xcos(x))/y ,y(0)=-2 ?

The solution for (dy}{dx}=\frac{xcos(x))/y ,y(0)=-2 is y=-sqrt(2xsin(x)+2cos(x)+2)

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(dy}{dx}=\frac{xcos(x))/y ,y(0)=-2

\frac{d y}{d x} = \frac{x cos ( x )}{y}, y (0) = - 2

y = - 2 x sin (x) + 2 cos (x) + 2

Solution steps

\frac{d y}{d x} = \frac{x cos ( x )}{y}

Solve separable ODE:

y = - 2 x sin (x) + 2 cos (x) + 2

y = - 2 x sin (x) + 2 cos (x) + 2

e^{y} y^{^{'}} = \frac{( ( ln ( t ) ) ^{2} )}{t}

\frac{d y}{d u} + 3 u^{2} y = 5 u^{2}

\frac{d Q}{d t} = \frac{50 - Q}{10}

y^{2} (x d y - y d x) = 9 x^{2} (y d x - x d y)

\frac{d z}{d t} = 2 t e^{2 z}

What is the solution for (dy}{dx}=\frac{xcos(x))/y ,y(0)=-2 ?
The solution for (dy}{dx}=\frac{xcos(x))/y ,y(0)=-2 is y=-sqrt(2xsin(x)+2cos(x)+2)