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Popular >

3y+y^'=0

Solution

3 y + y^{^{'}} = 0

Solution

y = e^{- 3 t + c_{1}}

Solution steps

3 y + y^{'} (t) = 0

Solve separable ODE:

y = e^{- 3 t + c_{1}}

y = e^{- 3 t + c_{1}}

Graph

Popular Examples

x y^{^{'}} = (x^{2} - 1) y

y^{^{'}} \cdot tan (x) = y

(dy)/(dx)=(3x-2)^3e^{2y},y=0,x=1

\frac{d y}{d x} = (3 x - 2)^{3} e^{2 y}, y = 0, x = 1

(dy)/(dt)y= 1/(2sqrt(81))*9

\frac{d y}{d t} y = \frac{1}{2 81} \cdot 9

(dy)/(dx)= y/((2x))

\frac{d y}{d x} = \frac{y}{( 2 x )}

Frequently Asked Questions (FAQ)

What is the solution for 3y+y^'=0 ?
The solution for 3y+y^'=0 is y=e^{-3t+c_{1}}