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Popular >

y^'=-2/y

Solution

y^{^{'}} = - \frac{2}{y}

Solution

y = - 4 t + c_{1}, y = - - 4 t + c_{1}

Solution steps

y^{'} (t) = - \frac{2}{y}

Solve separable ODE:

y = - 4 t + c_{1}, y = - - 4 t + c_{1}

y = - 4 t + c_{1}, y = - - 4 t + c_{1}

Graph

Popular Examples

y^'=e^{3y+3t},y(0)=-12

y^{^{'}} = e^{3 y + 3 t}, y (0) = - 12

y^'+1/(1+x)y= 2/(1+x)

y^{^{'}} + \frac{1}{1 + x} y = \frac{2}{1 + x}

11x-8ysqrt(x^2+1)(dy)/(dx)=0,y(0)=3

11 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = 3

y^'=1-x+y-xy,y(0)=0

y^{^{'}} = 1 - x + y - x y, y (0) = 0

5y^'=ycos(x),y(0)=2

5 y^{^{'}} = y cos (x), y (0) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=-2/y ?
The solution for y^'=-2/y is y=sqrt(-4t+c_{1)},y=-sqrt(-4t+c_{1)}