What is the first derivative of y=x-3 ?

The first derivative of y=x-3 is 1

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derivative of y=x-3

derivative of

y = x - 3

1

Solution steps

\frac{d}{d x} (x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (3)

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 1 - 0

Simplify

= 1

\frac{d}{d x} (arctan (\frac{x - 1}{x + 1}))

\frac{\partial}{\partial y} (x^{2} y - 2 x^{2} - 4 y^{2})

\frac{4 x - 5}{3 x + 2}

\frac{d}{d x} (\frac{11 x}{( 2 + x ^{2} )})

x = 64 - y^{2}, x = y^{2} - 64