What is the solution for (dy)/(dx)=(2xy)/((ln(y))^2) ?

The solution for (dy)/(dx)=(2xy)/((ln(y))^2) is y=e^{\sqrt[3]{3x^2+c_{1}}}

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(dy)/(dx)=(2xy)/((ln(y))^2)

\frac{d y}{d x} = \frac{2 x y}{( ln ( y ) ) ^{2}}

y = e^{3 3 x^{2} + c_{1}}

Solution steps

\frac{d y}{d x} = \frac{2 x y}{( ln ( y ) ) ^{2}}

Solve separable ODE:

y = e^{3 3 x^{2} + c_{1}}

y = e^{3 3 x^{2} + c_{1}}

x^{2} \cdot y^{^{'}} - y = 0

\frac{d y}{d x} = \frac{1}{4} e^{- 2 y}, y (0) = 0

\frac{d y}{d x} = \frac{( 2 y ln ( y ) )}{( x )}, y (1) = 4

y \frac{d y}{d x} - x y^{2} + x = 0

y^{^{'}} - 6 x y = 0, y (1) = 1

What is the solution for (dy)/(dx)=(2xy)/((ln(y))^2) ?
The solution for (dy)/(dx)=(2xy)/((ln(y))^2) is y=e^{\sqrt[3]{3x^2+c_{1}}}