What is the solution for (dy)/(dx)=8y(-3-y) ?

The solution for (dy)/(dx)=8y(-3-y) is y=-3/(1-e^{3(8x+c_{1))}}

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(dy)/(dx)=8y(-3-y)

\frac{d y}{d x} = 8 y (- 3 - y)

y = - \frac{3}{1 - e ^{3 (8 x + c_{1})}}

Solution steps

\frac{d y}{d x} = 8 y (- 3 - y)

Solve separable ODE:

y = - \frac{3}{1 - e ^{3 (8 x + c_{1})}}

y = - \frac{3}{1 - e ^{3 (8 x + c_{1})}}

\frac{d y}{d x} = ((1 + 2 x) y)

e^{- x^{2}} \frac{d y}{d x} = x (y + 2)^{2}, y (1) = 2

y^{^{'}} = y ln (y) cot (x)

\frac{d y}{d t} = - \frac{y}{( \frac{4320}{7} )}

2 x^{2} y - 4 x y^{^{'}} + 6 y = 0

What is the solution for (dy)/(dx)=8y(-3-y) ?
The solution for (dy)/(dx)=8y(-3-y) is y=-3/(1-e^{3(8x+c_{1))}}