What is the solution for (dy}{dx}=\frac{2x^4)/y ?

The solution for (dy}{dx}=\frac{2x^4)/y is y=sqrt((4x^5)/5+c_{1)},y=-sqrt((4x^5)/5+c_{1)}

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(dy}{dx}=\frac{2x^4)/y

\frac{d y}{d x} = \frac{2 x ^{4}}{y}

y = \frac{4 x ^{5}}{5} + c_{1}, y = - \frac{4 x ^{5}}{5} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{2 x ^{4}}{y}

Solve separable ODE:

y = \frac{4 x ^{5}}{5} + c_{1}, y = - \frac{4 x ^{5}}{5} + c_{1}

y = \frac{4 x ^{5}}{5} + c_{1}, y = - \frac{4 x ^{5}}{5} + c_{1}

\frac{d y}{d x} - cos (x) y = cos (x)

6 x^{4} d y = 3 y^{3} d x

y - 10 = \frac{d y}{d x}

y^{^{'}} = - y^{2} + 15 y - 50

\frac{d y}{d x} = \frac{( y x + 3 x - y - 3 )}{x y - 2 x + 4 y - 8}

What is the solution for (dy}{dx}=\frac{2x^4)/y ?
The solution for (dy}{dx}=\frac{2x^4)/y is y=sqrt((4x^5)/5+c_{1)},y=-sqrt((4x^5)/5+c_{1)}