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Popular >

x^3y^'=y^2(x-4)

Solution

x^{3} y^{^{'}} = y^{2} (x - 4)

Solution

y = - \frac{x ^{2}}{- x + 2 + c _{1} x ^{2}}

Solution steps

x^{3} y^{'} (x) = y^{2} (x - 4)

Solve separable ODE:

y = - \frac{x ^{2}}{- x + 2 + c _{1} x ^{2}}

y = - \frac{x ^{2}}{- x + 2 + c _{1} x ^{2}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for x^3y^'=y^2(x-4) ?
The solution for x^3y^'=y^2(x-4) is y=-(x^2)/(-x+2+c_{1)x^2}