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Popular >

(x^2+9)y^'=xy

Solution

(x^{2} + 9) y^{^{'}} = x y

Solution

y = c_{1} x^{2} + 9

Solution steps

(x^{2} + 9) y^{'} (x) = x y

Solve separable ODE:

y = c_{1} x^{2} + 9

y = c_{1} x^{2} + 9

Graph

Popular Examples

y^'=(y+1)/(x+1)

y^{^{'}} = \frac{y + 1}{x + 1}

(dy)/(dx)=(4y^{3/4})/(x^2+1),y(0)=1

\frac{d y}{d x} = \frac{4 y ^{\frac{3}{4}}}{x ^{2} + 1}, y (0) = 1

(dy)/(dt)=-1/50 (y-21)

\frac{d y}{d t} = - \frac{1}{50} (y - 21)

(dy)/(dx)=(-y)/(3x)

\frac{d y}{d x} = \frac{- y}{3 x}

2sqrt(xy)*(dy)/(dx)=1

2 x y \cdot \frac{d y}{d x} = 1

Frequently Asked Questions (FAQ)

What is the solution for (x^2+9)y^'=xy ?
The solution for (x^2+9)y^'=xy is y=c_{1}sqrt(x^2+9)