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Popular >

y^'=xy-x

Solution

y^{^{'}} = x y - x

Solution

y = e^{\frac{x ^{2}}{2} + c_{1}} + 1

Solution steps

y^{'} (x) = x y - x

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + c_{1}} + 1

y = e^{\frac{x ^{2}}{2} + c_{1}} + 1

Graph

Popular Examples

(x^2y^2)dx-1/(xy)dy=0

(x^{2} y^{2}) d x - \frac{1}{x y} d y = 0

(dx)/(dy)=(xy^3)/(sqrt(1+x^2))

\frac{d x}{d y} = \frac{x y ^{3}}{1 + x ^{2}}

2x-6y^2(dy)/(dx)+4=0

2 x - 6 y^{2} \frac{d y}{d x} + 4 = 0

(dy)/(dx)= x/(e^{-y)(1+x^2)^4}

\frac{d y}{d x} = \frac{x}{e ^{- y} ( 1 + x ^{2} ) ^{4}}

(3x^2+2)^2y^'-xy^2=0,y(0)= 3/2

(3 x^{2} + 2)^{2} y^{^{'}} - x y^{2} = 0, y (0) = \frac{3}{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=xy-x ?
The solution for y^'=xy-x is y=e^{(x^2)/2+c_{1}}+1