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Popular >

x^'=x^3,x(0)=1

Solution

x^{^{'}} = x^{3}, x (0) = 1

Solution

x = - \frac{1}{2 t - 1}

Solution steps

x^{'} (t) = x^{3}

Solve separable ODE:

x = - \frac{1}{2 t - 1}

x = - \frac{1}{2 t - 1}

Graph

Popular Examples

1+t=2tx(dx)/(dt)

1 + t = 2 t x \frac{d x}{d t}

2y(x^2+1)dy=xdx

2 y (x^{2} + 1) d y = x d x

y^2e^x+3ye^{2x}(dy)/(dx)=2e^x,y(0)=1

y^{2} e^{x} + 3 y e^{2 x} \frac{d y}{d x} = 2 e^{x}, y (0) = 1

(x^2}{y^2-1}y^'=\frac{3x^3)/y

\frac{x ^{2}}{y ^{2} - 1} y^{^{'}} = \frac{3 x ^{3}}{y}

y^{^{'}} = 9 y

Frequently Asked Questions (FAQ)

What is the solution for x^'=x^3,x(0)=1 ?
The solution for x^'=x^3,x(0)=1 is x=sqrt(-1/(2t-1))