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Popular >

x^'+x=-1

Solution

x^{^{'}} + x = - 1

Solution

x = e^{- t - c_{1}} - 1

Solution steps

x^{'} (t) + x = - 1

Solve separable ODE:

x = e^{- t - c_{1}} - 1

x = e^{- t - c_{1}} - 1

Graph

Popular Examples

y^'=(xysin(x^2))/(y+1)

y^{^{'}} = \frac{x y sin ( x ^{2} )}{y + 1}

(dy)/(dx)+yx^2=x^2

\frac{d y}{d x} + y x^{2} = x^{2}

y^{^{'}} = - (\frac{1}{5}) y^{2}

y^'=(cos^2(x))/(y^2),y(pi)=-1

y^{^{'}} = \frac{cos ^{2} ( x )}{y ^{2}}, y (π) = - 1

y(dy)/(dx)=4x(y^2+7)^9

y \frac{d y}{d x} = 4 x (y^{2} + 7)^{9}

Frequently Asked Questions (FAQ)

What is the solution for x^'+x=-1 ?
The solution for x^'+x=-1 is x=e^{-t-c_{1}}-1