What is the solution for (t^2-24t+119)(dy)/(dt)=y ?

The solution for (t^2-24t+119)(dy)/(dt)=y is y=(c_{1}\sqrt[10]{t-17})/(\sqrt[10]{t-7)}

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(t^2-24t+119)(dy)/(dt)=y

(t^{2} - 24 t + 119) \frac{d y}{d t} = y

y = \frac{c _{1} 10 t - 17}{10 t - 7}

Solution steps

(t^{2} - 24 t + 119) \frac{d y}{d t} = y

Solve separable ODE:

y = \frac{c _{1} 10 t - 17}{10 t - 7}

y = \frac{c _{1} 10 t - 17}{10 t - 7}

\frac{d y}{d t} = k (y + 2)

\frac{1}{8} \frac{d y}{d x} = y 4 x^{2} - 1

\frac{y ^{^{'}}}{x} = - y

y e^{- y} d y = - e^{x} x^{2} d x

\frac{d y}{d x} = 3 y, y (0) = 5

What is the solution for (t^2-24t+119)(dy)/(dt)=y ?
The solution for (t^2-24t+119)(dy)/(dt)=y is y=(c_{1}\sqrt[10]{t-17})/(\sqrt[10]{t-7)}