What is the solution for (dy)/(dx)=y(x^2+3) ?

The solution for (dy)/(dx)=y(x^2+3) is y=e^{(x^3)/3+3x+c_{1}}

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(dy)/(dx)=y(x^2+3)

\frac{d y}{d x} = y (x^{2} + 3)

y = e^{\frac{x ^{3}}{3} + 3 x + c_{1}}

Solution steps

\frac{d y}{d x} = y (x^{2} + 3)

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + 3 x + c_{1}}

y = e^{\frac{x ^{3}}{3} + 3 x + c_{1}}

\frac{d v}{d t} = 9.6138 - 8 v

\frac{d y}{d x} = - \frac{3 x + x y ^{2}}{2 y + x ^{2} y}

3 x^{2} (1 + y^{2}) d x - 2 y d y = 0

y^{^{'}} = \frac{11 x ^{2} - 1}{11 + 3 y}

\frac{d y}{d x} = \frac{cos ( x ) y}{2}

What is the solution for (dy)/(dx)=y(x^2+3) ?
The solution for (dy)/(dx)=y(x^2+3) is y=e^{(x^3)/3+3x+c_{1}}