What is the solution for (dy)/(dx)=2sqrt(1-y^2) ?

The solution for (dy)/(dx)=2sqrt(1-y^2) is y=sin(2x+c_{1})

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(dy)/(dx)=2sqrt(1-y^2)

\frac{d y}{d x} = 2 1 - y^{2}

y = sin (2 x + c_{1})

Solution steps

\frac{d y}{d x} = 2 1 - y^{2}

Solve separable ODE:

y = sin (2 x + c_{1})

y = sin (2 x + c_{1})

(2 + t) y^{^{'}} = 3 y

y^{^{'}} = \frac{3 x 16 + y ^{2}}{y}

y^{^{'}} = \frac{6 sin ( x )}{sin ( y )}

(\frac{d x}{d t}) = - x

2 v^{2} y^{2} d y + 2 v y^{3} d v + v^{2} y^{2} d y + y^{2} d y = 0

What is the solution for (dy)/(dx)=2sqrt(1-y^2) ?
The solution for (dy)/(dx)=2sqrt(1-y^2) is y=sin(2x+c_{1})