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Popular >

f^'(x)=f(x)(f(x))

Solution

f^{^{'}} (x) = f (x) (f (x))

Solution

f (x) = - \frac{1}{x + c _{1}}

Solution steps

f^{'} (x) = f (x) (f (x))

Solve separable ODE:

f (x) = - \frac{1}{x + c _{1}}

f (x) = - \frac{1}{x + c _{1}}

Graph

Popular Examples

y^'=(y-2)cot(x)

y^{^{'}} = (y - 2) cot (x)

y(dy)/(dx)=e^{x-y^2}

y \frac{d y}{d x} = e^{x - y^{2}}

(dy)/(dt)=1.5-0.01y,y(0)=5

\frac{d y}{d t} = 1.5 - 0.01 y, y (0) = 5

(dx)/(0.5+0.8x)=(dy)/(1.5-0.8y)

\frac{d x}{0.5 + 0.8 x} = \frac{d y}{1.5 - 0.8 y}

y^{^{'}} + 4 y = \frac{4}{3}

Frequently Asked Questions (FAQ)

What is the solution for f^'(x)=f(x)(f(x)) ?
The solution for f^'(x)=f(x)(f(x)) is f(x)=-1/(x+c_{1)}