What is the solution for (dy)/(dx)=((1-x^2))/(y^2) ?

The solution for (dy)/(dx)=((1-x^2))/(y^2) is y=\sqrt[3]{3x-x^3+c_{1}}

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(dy)/(dx)=((1-x^2))/(y^2)

\frac{d y}{d x} = \frac{( 1 - x ^{2} )}{y ^{2}}

y = 3 3 x - x^{3} + c_{1}

Solution steps

\frac{d y}{d x} = \frac{( 1 - x ^{2} )}{y ^{2}}

Solve separable ODE:

y = 3 3 x - x^{3} + c_{1}

y = 3 3 x - x^{3} + c_{1}

\frac{d y}{d t} + 20 y = 24, y (0) = 0

e^{2 x} y^{^{'}} = x (cos (y))^{2}

\frac{d y}{d x} = x (6 - y), y = 0, x = 0

x \cdot y^{^{'}} = 15 \cdot y \cdot x + 11 \cdot x

\frac{d x}{d t} + 5 x = \frac{12}{11}

What is the solution for (dy)/(dx)=((1-x^2))/(y^2) ?
The solution for (dy)/(dx)=((1-x^2))/(y^2) is y=\sqrt[3]{3x-x^3+c_{1}}