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Popular >

y^'-y-2=0

Solution

y^{^{'}} - y - 2 = 0

Solution

y = e^{t + c_{1}} - 2

Solution steps

y^{'} (t) - y - 2 = 0

Solve separable ODE:

y = e^{t + c_{1}} - 2

y = e^{t + c_{1}} - 2

Graph

Popular Examples

y^'=2xy^2,y(0)=-1/(x^2+c)

y^{^{'}} = 2 x y^{2}, y (0) = - \frac{1}{x ^{2} + c}

(dV)/(dt)=90-(5V)/(100)

\frac{d V}{d t} = 90 - \frac{5 V}{100}

(y^2+1)dx=(x^2+1)dy

(y^{2} + 1) d x = (x^{2} + 1) d y

(dy)/(dx)=15xsec(y)

\frac{d y}{d x} = 15 x sec (y)

y^'=(x^2)/(y+1),y(0)=4

y^{^{'}} = \frac{x ^{2}}{y + 1}, y (0) = 4

Frequently Asked Questions (FAQ)

What is the solution for y^'-y-2=0 ?
The solution for y^'-y-2=0 is y=e^{t+c_{1}}-2