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Popular >

(xln(x^2))y^'=2y

Solution

(x ln (x^{2})) y^{^{'}} = 2 y

Solution

y = c_{1} ln (x)

Solution steps

(x ln (x^{2})) y^{'} (x) = 2 y

Solve separable ODE:

y = c_{1} ln (x)

y = c_{1} ln (x)

Graph

Popular Examples

(dy)/(dt)+0.5ty=4t

\frac{d y}{d t} + 0.5 t y = 4 t

(dy}{dx}=\frac{y^2)/x ,y(e)=3

\frac{d y}{d x} = \frac{y ^{2}}{x}, y (e) = 3

1/y dy=(-x)/(sqrt(1+x^2))dx

\frac{1}{y} d y = \frac{- x}{1 + x ^{2}} d x

x^{^{'}} = 1 - 3 x + 2 x^{2}

(dy)/(dx)=-(x^3)/(y^3)

\frac{d y}{d x} = - \frac{x ^{3}}{y ^{3}}

Frequently Asked Questions (FAQ)

What is the solution for (xln(x^2))y^'=2y ?
The solution for (xln(x^2))y^'=2y is y=c_{1}ln(x)