What is the derivative of xy+y ?

The derivative of xy+y is y+x(dy)/(dx)+(dy)/(dx)

What is the first derivative of xy+y ?

The first derivative of xy+y is y+x(dy)/(dx)+(dy)/(dx)

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\frac{d}{d x} (x y + y)

y + x \frac{d y}{d x} + \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x y + y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x y) + \frac{d y}{d x}

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

= y + x \frac{d y}{d x} + \frac{d y}{d x}

f (x) = \frac{c ^{8} - x ^{8}}{c ^{8} + x ^{8}}

e^{2 x + 3}

\int 30 - 10 t d t

\int z z - 1 d z

\int e^{0.3 x} d x

What is the derivative of xy+y ?
The derivative of xy+y is y+x(dy)/(dx)+(dy)/(dx)
What is the first derivative of xy+y ?
The first derivative of xy+y is y+x(dy)/(dx)+(dy)/(dx)